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The daughter's head start in time

📖 The story

Father (52) and daughter (24) both want to save up $250,000 by age 60, both at 8 % return. The father has 8 years, the daughter 36 years.

ℹ  What is computed is the daughter's rate (36 years). With only 8 years the father would need many times as much.

Change any number and press "Calculate" – or use "Type in" on the right to watch it entered.

What you learn

Time beats money dramatically: the daughter reaches the same goal with a fraction of the father's rate. Quadrupling the saving time does not demand a quarter, but less than a twentieth of the rate.

In short: The same target amount costs the daughter only a fraction of the father's rate thanks to time – starting early beats any saving effort.
Formula
R = (FV − K0·q^n) / ((q^n − 1)/(q − 1))
With the example numbers
R = 250.000,00 € / ((qn−1)/(q−1)),  q = 1,006434, n = 432 = 107,46 €
How to read the formula

Here the final-value formula is solved for the rate: you divide the target by the compounding factor (qⁿ−1)/(q−1), which shows the multiple to which a rate of $1 grows. Takeaway: the longer n, the larger this factor – and the smaller the rate needed.

More values
Sparrate vater 8j 1,890.29

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